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Answer :
Let x be the number of hours exercising horses.
Let y be the number of hours cleaning stalls.
x + y <= 12
5x + 10y >= 60
x + 2y >= 12
At this point you might do well to graph this set of equations on Wolframalpha.com
In the meantime solve this system this way.
12 - x > y > 6 - x/2
When y =0 the x = 12.
Let y be the number of hours cleaning stalls.
x + y <= 12
5x + 10y >= 60
x + 2y >= 12
At this point you might do well to graph this set of equations on Wolframalpha.com
In the meantime solve this system this way.
12 - x > y > 6 - x/2
When y =0 the x = 12.
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Answer: 5x + 10y ≥ 60 ⇒ x+2y ≥ 12 .................. (i)
x + y ≤ 12 ................. (ii)
Step-by-step explanation:
Let the hours spent on exercising horse be x
Let the hours spent on cleaning stalls be y
According to question:
Rob can't work more than 12 hours. So eq. (i) will be x + y ≤ 12
Rob earns $5 an hour by exercising horses and $10 an hour cleaning stalls and he must make $60 . So eq. (ii) will be 5x + 10y ≥ 60.
Dividing eq. (ii) by 5, it will become x + 2y ≥ 12.
∴ system of inequalities are x + y ≤ 12 and x + 2y ≥ 12.