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Answer :
Answer:
1291.08 N
Explanation:
acceleration=change in speed per unit time
[tex]a=\frac {v-u}{t}[/tex] where v and u are final and initial velocities respectively.
u is zero and v=160 km/h converted to m/s becomes[tex]160\times \frac {1000m}{3600s}\approx 44.44 m/s[/tex]
acceleration=[tex]\frac {44.44-0}{8}\approx 5.56 m/s^{2}[/tex]
Apparent weight, [tex]F_N=m(g+a)[/tex]
Taking g as 9.81 and m as 84 Kg then
[tex]F_N=84(9.81+5.56)\approx 1291.08 N[/tex]
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Final answer:
The astronaut's apparent weight just after launch is about 467.04 N. This is calculated using the equation F = ma, where m is the astronaut's mass and a is the shuttle's acceleration (derived from the given final velocity and time).
Explanation:
To calculate the apparent weight of the astronaut, we need to find the acceleration of the shuttle first. We'll use the formula v = u + at, where v is the final velocity, u is the initial velocity (zero in this case as it's a vertical launch), a is the acceleration, and t is the time. We're given that v = 160 km/h which is equivalent to 44.44 meters per second (160000 m / 3600 seconds) and t = 8 seconds.
Calculating for a = (v - u) / t, we get a = 5.56 m/s². Then we calculate the apparent weight using the equation F = ma, where F is the force (apparent weight) and m is the mass. Using m = 84 kg and a = 5.56 m/s², we find that F (the apparent weight) = 467.04 N (rounded to the nearest hundredths place).
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