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Answer :
Answer: A f(2)=0 I think
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Rewritten by : Barada
Answer:
f(2) = 0
f(-4) = 24
Step-by-step explanation:
[tex] \hookrightarrow \: { \tt{ \sf{f(n) = {n}^{2} - 2n }}}[/tex]
When n is 2 ✔
[tex] \dashrightarrow \: { \tt{f(2) = {(2)}^{2} - (2 \times 2) = 4 - 4 = 0}} \\ [/tex]
When n is -2 ✖
[tex] \dashrightarrow { \tt{ {( - 2)}^{2} - (2 \times - 2) = 4 + 4 = 8 }}[/tex]
When n is 1 ✖
[tex] \dashrightarrow{ \tt{f(1) = {(1)}^{2} - (2 \times 1) = - 1 }}[/tex]
When n is 5 ✖
[tex] \dashrightarrow{ \tt{f(5) = {(5)}^{2} - (2 \times 5) = 15}}[/tex]
When n is -4 ✔
[tex] \dashrightarrow{ \tt{f( - 4) = {( - 4)}^{2} - (2 \times - 4) }} \\ { \tt{ = 16 + 8}} \\ { \tt{ = 24}}[/tex]
