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Answer :
Answer:
Part a) Higher fee per game Arcade A
Part b) Higher entrance fee Arcade B
Part c) Higher total cost for 8 games Arcade B
Step-by-step explanation:
Let
x------> the number of games
Arcade A
we have that the linear equation is
[tex]y=0.75x+2[/tex]
The fee per game is $0.75
The entrance fee is $2
The cost for 8 games is equal to
[tex]y=0.75(8)+2=\$8[/tex]
Arcade B
Find the linear equation
Let
[tex]A(0,8),B(4,10)[/tex]
Find the slope of the line (fee per game)
[tex]m=\frac{10-8}{4-0}=0.50[/tex]
The point A is the y-intercept
The linear equation is
[tex]y=0.50x+8[/tex]
so
The fee per game is $0.50
The entrance fee is $8
The cost for 8 games is equal to
[tex]y=0.50(8)+8=\$12[/tex]
therefore
Part a) Higher fee per game Arcade A
Part b) Higher entrance fee Arcade B
Part c) Higher total cost for 8 games Arcade B
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