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One particular cone of dry sand is 33 feet tall with a base diameter of 97.8 feet. To the nearest tenth of a degree, what is the angle of repose of this type of dry sand?

Answer :

Answer:

Angle of repose of the cone of dry stand is 34.0°

Step-by-step explanation:

Angle of repose of a cone shaped mountain is the angle between base of the mountain and height as shown in the figure attached.

From the triangle ABC,

tanB = [tex]\frac{AD}{BD}[/tex]

= [tex]\frac{AD}{\frac{BC}{2}}[/tex]

= [tex]\frac{33}{\frac{97.8}{2} }[/tex]

= [tex]\frac{66}{97.8}[/tex]

tanB = 0.6748

B = [tex]tan^{-1}(0.6748)[/tex]

= 34.01°≈ 34.0°

Therefore, angle of repose of the cone of dry stand is 34.0°

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Rewritten by : Barada

Answer:

This forms a right triangle with height = 33 and side = 48.9

arc tan (angle) = 33/48.9

arc tan (angle) = 0.6748466258

angle = 34.0 Degrees

Step-by-step explanation: