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A sample of gold has a volume of 2 cm³ and a mass of 38.6 grams.

1. What is the density of the sample?
2. List three other properties of the sample that would be considered physical properties.

Answer :

The density of the gold is calculated to be "19,300 kg/m³".

Explanation:

Given:

Volume = 2cm³

Mass = 38.6 grams.

To Find:

Density of the gold = ?

Solution:

Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.

Mass in grams is converted into kg as,

1 g = 0.001 kg

38. 6 g = [tex]\frac{38.6}{1000} = 0.0386 kg[/tex]

Now we have to convert cm³ to m³ as,

1 cm³ = 10⁻⁶ m³

2 cm³ = 2 × 10⁻⁶ m³

So Density = [tex]\frac{0.0386 k g}{2 \times 10^{-6} m^{3}}=19,300 \mathrm{kg} / \mathrm{m}^{3}[/tex]

Physical properties of Gold:

  • Gold is a heavy metal.
  • It is Malleable and ductile.
  • It is a corrosion resistant element.

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Rewritten by : Barada

Final answer:

The density of the gold sample is 19.3 g/cm³. Other physical properties include its color, luster, and malleability.

Explanation:

The density of a substance is determined by dividing its mass by its volume. In this case, the density of the gold sample would be calculated as 38.6 grams divided by 2 cm³, which equals 19.3 g/cm³. Therefore, the density of this gold sample is 19.3 g/cm³.

Aside from density, three other physical properties of the gold sample could include its color (gold), its luster (shiny), and its malleability (ability to be shaped or formed without breaking).

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