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Answer:
[tex]\boxed{HA}[/tex]
Step-by-step explanation:
The theorem that verifies ΔHIJ ≅ ΔKLM is the HA (Hypotenuse-Angle Theorem) which shows that the hypotenuse and an acute angle are congruent to each other.
=> IJ ≅ LM (Hypotenuse)
=> ∠NIJ ≅ ∠KLM (Acute Angle)
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Rewritten by : Barada
Answer:
D
Step-by-step explanation:
We see that one corresponding angle and the hypotenuses of the right triangles are congruent so the answer is HA. (The H stands for hypotenuse and the A stands for angle.)
