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Answer :
Our three consecutive integers can be represented as
X → first integer
X + 1 → second integer
X + 2 → third integer
If the sum of our three consecutive integers is 141, our equation will read...
X + X + 1 + X + 2 = 141
Now, we can simplify on the left. Once we simplify, our equation will now read
3x + 3 = 141
-3 -3 ← subtract 3 on both sides
3x = 138 ← divide by 3 on both sides
X = 46 ← smallest integer
Therefore, the smallest integer is 46.
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Rewritten by : Barada
Let x=the smallest integer, x+1=the second smallest, x+2=the greatest.
x+x+1+x+2=141
3x+3=141
3x=138
x=46
46 is the smallest integer
x+x+1+x+2=141
3x+3=141
3x=138
x=46
46 is the smallest integer
