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Answer :
To solve this problem, recall the formula that relates momentum, mass, and velocity. The momentum equation is given by
[tex]$$
p = m \cdot v,
$$[/tex]
where
- [tex]$p$[/tex] is the momentum,
- [tex]$m$[/tex] is the mass, and
- [tex]$v$[/tex] is the velocity.
We are given that the momentum is [tex]$36\,\text{kg}\cdot\text{m/s}$[/tex] and the velocity is [tex]$4\,\text{m/s}$[/tex]. To find the mass, we rearrange the equation to solve for [tex]$m$[/tex]:
[tex]$$
m = \frac{p}{v}.
$$[/tex]
Substituting the given values into the equation:
[tex]$$
m = \frac{36\,\text{kg}\cdot\text{m/s}}{4\,\text{m/s}}.
$$[/tex]
Performing the division:
[tex]$$
m = 9\,\text{kg}.
$$[/tex]
Thus, the mass of the bicycle is [tex]$\boxed{9\,\text{kg}}$[/tex].
[tex]$$
p = m \cdot v,
$$[/tex]
where
- [tex]$p$[/tex] is the momentum,
- [tex]$m$[/tex] is the mass, and
- [tex]$v$[/tex] is the velocity.
We are given that the momentum is [tex]$36\,\text{kg}\cdot\text{m/s}$[/tex] and the velocity is [tex]$4\,\text{m/s}$[/tex]. To find the mass, we rearrange the equation to solve for [tex]$m$[/tex]:
[tex]$$
m = \frac{p}{v}.
$$[/tex]
Substituting the given values into the equation:
[tex]$$
m = \frac{36\,\text{kg}\cdot\text{m/s}}{4\,\text{m/s}}.
$$[/tex]
Performing the division:
[tex]$$
m = 9\,\text{kg}.
$$[/tex]
Thus, the mass of the bicycle is [tex]$\boxed{9\,\text{kg}}$[/tex].
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