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Paula caught a tarpon with a weight that was 11 times the weight of a permit fish she caught. The total weight of the two fish was 156 pounds.

How much did each fish weigh?

Answer :

Answer:

Let one fish weigh xlbs and other 11xlbs

Step-by-step explanation:









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Rewritten by : Barada

Final answer:

To solve the problem, set up two equations based on the information given: T=11P and T+P=156. Substitute T=11P into the second equation to find P=13. Finally, substitute P=13 into the T=11P equation to find T=143 pounds.

Explanation:

First, we need to start off by defining a couple of variables to represent the weight of the two species of fish caught by Paula. Let's let P represent the weight in pounds of the permit fish, and T represent the weight in pounds of the tarpon.

According to the question, the tarpon was 11 times the weight of the permit fish, which can be represented as T=11P. It's also mentioned that the total weight of both fish is 156 pounds, which can be represented as T+P=156. Since we now have two equations, we can substitute T=11P into the second equation, which becomes 11P+P=156. This simplifies to 12P=156. Dividing both sides of the equation by 12 gives us P=13, meaning the permit fish weighed 13 pounds. Substituting P=13 into the equation T=11P gives us the weight of the tarpon, T=11*13, so T = 143 pounds.

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