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Answer :
To find the product of [tex]\(2x^4(4x^2 + 3x + 1)\)[/tex], we need to distribute and multiply each term inside the parenthesis by [tex]\(2x^4\)[/tex]. Let's go through this process step-by-step:
1. Multiply [tex]\(2x^4\)[/tex] with the first term inside the parenthesis:
[tex]\[
2x^4 \times 4x^2 = 8x^{4+2} = 8x^6
\][/tex]
2. Multiply [tex]\(2x^4\)[/tex] with the second term inside the parenthesis:
[tex]\[
2x^4 \times 3x = 6x^{4+1} = 6x^5
\][/tex]
3. Multiply [tex]\(2x^4\)[/tex] with the third term inside the parenthesis:
[tex]\[
2x^4 \times 1 = 2x^4
\][/tex]
Finally, combine all these products to get the final expression:
[tex]\[
8x^6 + 6x^5 + 2x^4
\][/tex]
This is the expanded form of the expression and your answer.
1. Multiply [tex]\(2x^4\)[/tex] with the first term inside the parenthesis:
[tex]\[
2x^4 \times 4x^2 = 8x^{4+2} = 8x^6
\][/tex]
2. Multiply [tex]\(2x^4\)[/tex] with the second term inside the parenthesis:
[tex]\[
2x^4 \times 3x = 6x^{4+1} = 6x^5
\][/tex]
3. Multiply [tex]\(2x^4\)[/tex] with the third term inside the parenthesis:
[tex]\[
2x^4 \times 1 = 2x^4
\][/tex]
Finally, combine all these products to get the final expression:
[tex]\[
8x^6 + 6x^5 + 2x^4
\][/tex]
This is the expanded form of the expression and your answer.
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