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Answer :
To find the force exerted by the snowmobile to accelerate Sully, we can use the formula [tex]\( F = m \cdot a \)[/tex], where [tex]\( F \)[/tex] is the force, [tex]\( m \)[/tex] is the mass, and [tex]\( a \)[/tex] is the acceleration.
1. Identify the initial and final velocities:
- Initial velocity ([tex]\( v_i \)[/tex]) is 10 meters/second.
- Final velocity ([tex]\( v_f \)[/tex]) is 16 meters/second.
2. Determine the time over which the acceleration occurs:
- Time ([tex]\( t \)[/tex]) is 10 seconds.
3. Calculate the acceleration:
- Acceleration ([tex]\( a \)[/tex]) is the change in velocity divided by time.
- Formula: [tex]\( a = \frac{v_f - v_i}{t} \)[/tex].
- Substitute the values: [tex]\( a = \frac{16 - 10}{10} = \frac{6}{10} = 0.6 \)[/tex] meters/second².
4. Determine the mass of the snowmobile, including Sully:
- Mass ([tex]\( m \)[/tex]) is 280 kilograms.
5. Calculate the force using the formula [tex]\( F = m \cdot a \)[/tex]:
- Substitute the values: [tex]\( F = 280 \cdot 0.6 = 168 \)[/tex] Newtons.
Therefore, the force exerted by the snowmobile to accelerate is 168 N, which matches option B.
1. Identify the initial and final velocities:
- Initial velocity ([tex]\( v_i \)[/tex]) is 10 meters/second.
- Final velocity ([tex]\( v_f \)[/tex]) is 16 meters/second.
2. Determine the time over which the acceleration occurs:
- Time ([tex]\( t \)[/tex]) is 10 seconds.
3. Calculate the acceleration:
- Acceleration ([tex]\( a \)[/tex]) is the change in velocity divided by time.
- Formula: [tex]\( a = \frac{v_f - v_i}{t} \)[/tex].
- Substitute the values: [tex]\( a = \frac{16 - 10}{10} = \frac{6}{10} = 0.6 \)[/tex] meters/second².
4. Determine the mass of the snowmobile, including Sully:
- Mass ([tex]\( m \)[/tex]) is 280 kilograms.
5. Calculate the force using the formula [tex]\( F = m \cdot a \)[/tex]:
- Substitute the values: [tex]\( F = 280 \cdot 0.6 = 168 \)[/tex] Newtons.
Therefore, the force exerted by the snowmobile to accelerate is 168 N, which matches option B.
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