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The potential difference between the terminals of a battery is 50 V when 10 A is being drawn from it, and 54 V when the current is 6 A. What is the internal resistance of the battery?

A. 1 Ω
B. 2 Ω
C. 0.1 Ω
D. 0.2 Ω
E. 0.01 Ω

Answer :

Final answer:

The internal resistance of the battery is 5 Ω.


Explanation:

The internal resistance of a battery can be calculated using Ohm's law and the concept of potential difference. Ohm's law states that voltage is equal to current multiplied by resistance, or V = I * R. In this case, we have two different voltage-current pairs: (50 V, 10 A) and (54 V, 6 A). To find the internal resistance, we can calculate the resistance using either of the pairs and substitute it into Ohm's law.

Let's use the first pair: 50 V = 10 A * R. Solving for R, we get R = 5 Ω. Therefore, the internal resistance of the battery is 5 Ω.


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