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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If the heterozygous [tex]WW[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Answer :

Certainly! Let's go through each part of the problem step-by-step.

### Part 1: Probability of Heterozygous Offspring (Ww)

1. Parental Genotypes:
- The male is heterozygous with genotype Ww.
- The female is homozygous recessive with genotype ww.

2. Possible Offspring Genotypes:
To find the possible genotypes of the offspring, we perform a Punnett square analysis:
- One parent contributes the alleles W or w.
- The other parent contributes the allele w.

```
| | W | w |
|---|----|----|
| w | Ww | ww |
| w | Ww | ww |
```

3. Results:
- We have two Ww and two ww genotypes from the square.

4. Probability Calculation:
- Total possible outcomes: 4 (Ww, Ww, ww, ww)
- Number of heterozygous outcomes (Ww): 2

Therefore, the probability of the offspring being heterozygous (Ww) is [tex]\((2/4) \times 100 = 50\%\)[/tex].

### Part 2: Probability of Homozygous Recessive Offspring (ww)

1. Parental Genotypes:
- The first parent is homozygous dominant with genotype WW.
- The second parent is also homozygous dominant with genotype WW.

2. Possible Offspring Genotypes:
- Each parent contributes a W allele, no matter what.
- The resulting genotypes are:

```
| | W | W |
|---|----|----|
| W | WW | WW |
| W | WW | WW |
```

3. Results:
- All offspring have the genotype WW.

4. Probability Calculation:
- Total possible outcomes: 4 (WW, WW, WW, WW)
- Number of homozygous recessive outcomes (ww): 0

Thus, the probability of having a homozygous recessive (ww) offspring is [tex]\((0/4) \times 100 = 0\%\)[/tex].

In conclusion, 50% of the offspring will be heterozygous (Ww) in the first scenario, and there is a 0% chance of having a homozygous recessive offspring (ww) in the second scenario.

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