We appreciate your visit to A 9 91 mL aliquot of the above diluted solution is further diluted to the mark in another 100 00 mL volumetric flask What is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The final concentration of sodium in the diluted solution is approximately 9.91 ppm after diluting a stock solution assumed to be 100 ppm by a factor of approximately 10.09.
Explanation:
The problem requires us to find the final concentration of sodium (Na) in parts per million (ppm), after a serial dilution is performed. First, 9.91 mL of the stock solution is diluted to 100.00 mL, thereby diluting it by a factor of [100.00 mL / 9.91 mL = approximately 10.09]. We assume the initial concentration of the stock solution to be 100 ppm of Na as no initial concentration is given and the student question references a stock solution with 100 ppm of analyte.
To find the final concentration after dilution, we divide the initial concentration by the dilution factor. Therefore, the final concentration after dilution will be: [100 ppm / 10.09 = approximately 9.91 ppm], which is option c).
Thanks for taking the time to read A 9 91 mL aliquot of the above diluted solution is further diluted to the mark in another 100 00 mL volumetric flask What is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
