High School

We appreciate your visit to A parallel plate capacitor holds tex 2 00 times 10 2 mu text C tex of charge when a potential difference of tex 5 00. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A parallel-plate capacitor holds [tex]2.00 \times 10^2 \, \mu\text{C}[/tex] of charge when a potential difference of [tex]5.00 \times 10^2 \, \text{V}[/tex] is applied between its plates. What is the capacitor's capacity in units of farads and in units of nanofarads?

A) [tex]4.00 \, \text{F}[/tex] and [tex]4.00 \times 10^6 \, \text{nF}[/tex]
B) [tex]2.50 \, \text{F}[/tex] and [tex]2.50 \times 10^6 \, \text{nF}[/tex]
C) [tex]2.00 \, \text{F}[/tex] and [tex]2.00 \times 10^6 \, \text{nF}[/tex]
D) [tex]2.00 \times 10^6 \, \text{F}[/tex] and [tex]2.00 \, \text{nF}[/tex]

Answer :

Final answer:

The parallel-plate capacitor's capacity is calculated by dividing the charge by the voltage. Upon applying correct conversions, it's found to be 4.00 x 10^-7 F in units of farads and 400 nF in units of nanofarads.

Explanation:

The capacitance of a capacitor, denoted by the symbol C, is defined by the relationship Q = CV where Q represents the charge stored on the capacitor, V is the voltage applied across the capacitor, and C is the capacitance. This equation can be rearranged to solve for capacitance, giving C = Q/V. In this case, the charge Q is 2.00 x 10^2 μC and the voltage V is 5.00 x 10^2 V. Note that we need to convert the charge from μC to C before performing the calculation. So the charge in coulombs is 2.00 x 10^2 x 10^-6 C = 2.00 x 10^-4 C. Using these values in our equation, we find C = 2.00 x 10^-4 C / 5.00 x 10^2 V = 4.00 x 10^-7 F or 0.4 μF. Since 1 μF equals 10^3 nF, the capacitance also equals 400 nF. Hence the parallel-plate capacitor's capacity is 4.00 x 10^-7 F in units of farads and 400 nF in units of nanofarads.

Learn more about Capacitance here:

https://brainly.com/question/31871398

#SPJ11

Thanks for taking the time to read A parallel plate capacitor holds tex 2 00 times 10 2 mu text C tex of charge when a potential difference of tex 5 00. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada