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At 6 a.m., the temperature in Lumpkin, Texas, was [tex]57 \degree F[/tex]. By 4 p.m., the temperature had risen to [tex]73 \degree F[/tex]. What was the change in temperature over the 10-hour period?

Answer :

Final answer:

The change in temperature over the 10-hour period in Lumpkin, Texas is found by subtracting the initial temperature (57°F at 6 am) from the final temperature (73°F at 4 pm), resulting in a rise of 16°F.

Explanation:

The subject of this question is Mathematics, which involves operations like subtraction in this context. To find the change in temperature over the 10-hour period in Lumpkin, Texas, you need to perform subtraction on the two temperatures given.

Initially, the temperature at 6 am was 57°F. By 4 pm, it had risen to 73°F. So, the change in temperature is calculated as follows:

  1. Subtract the initial temperature from the final temperature
  2. Therefore, 73°F (final) - 57°F (initial) = 16°F

Consequently, the change in temperature over the 10-hour period was 16°F.

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