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Select the correct answer.

Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the snowmobile, including Sully, is [tex]280[/tex] kilograms. If Sully accelerates to a velocity of 16 meters/second over [tex]10[/tex] seconds, what's the force exerted by the snowmobile to accelerate? Use [tex]F = ma[/tex], where [tex]a = \frac{\Delta v}{t}[/tex].

A. 160 N
B. 168 N
C. 248 N
D. 200 N
E. 324 N

Answer :

To solve this problem, we need to find the force exerted by the snowmobile to accelerate. We can use Newton's second law of motion, which states that force equals mass times acceleration, or [tex]\( F = m \times a \)[/tex].

Here's how to determine it step-by-step:

1. Identify the known values:
- Initial velocity ([tex]\( v_i \)[/tex]) = 10 meters/second
- Final velocity ([tex]\( v_f \)[/tex]) = 16 meters/second
- Time ([tex]\( t \)[/tex]) = 10 seconds
- Mass ([tex]\( m \)[/tex]) = 280 kilograms

2. Find the acceleration ([tex]\( a \)[/tex]):
- The formula for acceleration is [tex]\( a = \frac{v_f - v_i}{t} \)[/tex].
- Substitute the known values:
[tex]\[
a = \frac{16 \, \text{m/s} - 10 \, \text{m/s}}{10 \, \text{s}} = \frac{6 \, \text{m/s}}{10 \, \text{s}} = 0.6 \, \text{m/s}^2
\][/tex]

3. Calculate the force ([tex]\( F \)[/tex]):
- Use the formula [tex]\( F = m \times a \)[/tex].
- Substitute the values for mass and acceleration:
[tex]\[
F = 280 \, \text{kg} \times 0.6 \, \text{m/s}^2 = 168 \, \text{N}
\][/tex]

Therefore, the force exerted by the snowmobile to accelerate is 168 Newtons.

The correct answer is:
B. 168 N

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