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What is the volume in dL of a piece of ruthenium with a mass of 33.9 g? The density of ruthenium is 12.2 g/mL.

A) 27.7 dL
B) 2.78 dL
C) 0.278 dL
D) 0.0277 dL

Answer :

Final answer:

Given the mass and the density of ruthenium, we calculate its volume by dividing the mass by the density. After converting this to deciliters, we find the volume of a 33.9 g piece of ruthenium to be approximately 0.0277 dL.

Explanation:

To calculate the volume of a material given its mass and density, we use the formula V = m/d, where V is volume, m is mass, and d is density. Given that the mass (m) of the ruthenium is 33.9 g and the density (d) is 12.2 g/mL, we find the volume in milliliters (volume in mL = mass/density) which gives us approximately 2.78 mL. However, as the student needs the answer in deciliters (dL), we need to convert milliliters to deciliters. Knowing that 1 dL = 100 mL, the volume of ruthenium in deciliters is 2.78 mL * 0.01 dL/mL = 0.0278 dL. Therefore, the answer is D) 0.0277 dL (after rounding).

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