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Two aqueous solutions are separated by a selectively permeable membrane. Solution A contains 10 g of sucrose in 250 mL of water, while Solution B contains 25 g of sucrose in 625 mL of water. What is the expected result of osmosis?

A) Osmosis will not occur because the solutions are isotonic.
B) Osmosis will not occur because sucrose will not diffuse through the selectively permeable membrane.
C) Osmosis will occur from Solution A to Solution B.
D) Osmosis will occur from Solution B to Solution A.

Answer :

To determine the expected result of osmosis between the two solutions separated by a selectively permeable membrane, we first need to understand the concept of osmosis. Osmosis is the movement of water across a selectively permeable membrane from an area of lower solute concentration to an area of higher solute concentration. This process aims to equalize the concentration on both sides of the membrane.

Let's calculate the concentration of sucrose in each solution:

  1. Solution A:

    • Amount of sucrose = 10 grams
    • Volume of water = 250 mL
    • Concentration of sucrose in Solution A = [tex]\frac{10\, \text{g}}{250\, \text{mL}} = 0.04\, \text{g/mL}[/tex]

  2. Solution B:

    • Amount of sucrose = 25 grams
    • Volume of water = 625 mL
    • Concentration of sucrose in Solution B = [tex]\frac{25\, \text{g}}{625\, \text{mL}} = 0.04\, \text{g/mL}[/tex]

Both solutions have the same concentration of sucrose, which is 0.04 g/mL. Therefore, the solutions are isotonic relative to each other.

Given that osmosis occurs from the lower solute concentration to the higher solute concentration, and since both Solution A and Solution B have the same concentration of sucrose, osmosis will not occur in this situation.

Therefore, the correct answer is choice A) Osmosis will not occur because the solutions are isotonic.

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