Answer :

Final Answer:

It would take the 360m long train 24 seconds to pass a platform that is 900m long.

Explanation:

When a train passes a stationary object, it covers the length of the train itself in the time it takes to cross that object. In this case, the train is 360m long and takes 12 seconds to cross a pole, so its speed is 360m / 12s = 30 m/s.

When the train passes the 900m long platform, it needs to cover the sum of its own length and the platform's length. Therefore, it needs to cover a distance of 360m (train length) + 900m (platform length) = 1260m. At a speed of 30 m/s, it will take the train 1260m / 30 m/s = 42 seconds to pass the platform.

However, this time includes the time it takes for the front of the train to go from the start of the platform to the end of the platform. Since the train is already 360m into the platform when its front reaches the platform, the effective distance it needs to cover within the platform is reduced to 900m - 360m = 540m. At a speed of 30 m/s, it will take the train 540m / 30 m/s = 18 seconds to cover this distance.

Adding the time taken to cross the pole (12 seconds) and the time taken to cover the reduced distance within the platform (18 seconds), we get a total of 30 seconds.

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