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An airplane flying north at 800 miles per hour passes over a certain town at noon. A second airplane flying east at 500 miles per hour is directly over the same town 15 minutes later. If the airplanes are flying at the same altitude, how fast will they be separating at 1:15 P.M.?

Answer :

At 1:15 P.M., the two airplanes are separating at a rate of 943.4 miles per hour.

What is Speed?

speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.

Given, An airplane flying north at 800 miles per hour passes over a certain town at noon.

A second airplane going east at 500 miles per hour is directly over the same town 15 minutes later.

Let's assume that the town is located at the origin of a coordinate system. At noon, the first airplane is flying due north, so its velocity vector can be written as:

v₁ = <0, 800>

Similarly, at 12:15 P.M., the second airplane is flying due east, so its velocity vector can be written as:

v₂ = <500, 0>

To find the rate of separation between the two airplanes at 1:15 P.M., we need to find their relative velocity vector at that time. To do this, we can add their velocity vectors:

v = v₂ - v₁ = <500, 0> - <0, 800> = <500, -800>

This means that at 1:15 P.M., the two airplanes are separating at a rate of √(500² + (-800)²) miles per hour,

which is approximately 943.4 miles per hour (rounded to the nearest tenth).

Learn more about speed here:

https://brainly.com/question/28224010

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