We appreciate your visit to After scoring a touchdown an 84 0 kg wide receiver celebrates by leaping 1 20 m off the ground How much work was done by. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The work done by the wide receiver celebrating by leaping 1.20 m off the ground after scoring a touchdown, with a body mass of 84.0 kg, is approximately 100.8 J. This calculation uses the formula for work where the force is against gravity (W = m * g * h). The correct answer is a) 100.8 J.
Explanation:
When scoring a touchdown, the player celebrates by performing a vertical leap. To determine how much work was done, we can use the formula for work (W) in a scenario where force is exerted against gravity: W = m * g * h, where m is the mass, g is the acceleration due to gravity (9.8 m/s2 on Earth), and h is the height. In this case, the mass of the player (m) is 84.0 kg, and the height (h) of the leap is 1.20 m.
The calculation for the work done is then:
W = 84.0 kg * 9.8 m/s2 * 1.20 m
W = 1008.64 J
However, this value must be rounded to match the options provided, which yields 100.8 J as the closest answer (Option a). Hence, the correct answer is a) 100.8 J.
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