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Answer :
The periods of motion for the respective lengths are: [tex]1.000m: 1.996s[/tex]
[tex]0.750m: 1.732s[/tex], [tex]0.500m: 1.422s[/tex]
To determine the period of motion for each length of the simple pendulum, we divide the total time interval for [tex]50[/tex] oscillations by[tex]50[/tex]. The period (T) is defined as the time taken for one complete oscillation.
For a length of [tex]1.000m[/tex]:
Period (T) = Total time / Number of oscillations[tex]= 99.8s / 50 = 1.996s[/tex]
For a length of [tex]0.750m[/tex]
Period (T) = Total time / Number of oscillations[tex]= 86.6s / 50 = 1.732s[/tex]
For a length of [tex]0.500m:[/tex]
Period (T) = Total time / Number of oscillations [tex]= 71.1s / 50 = 1.422s[/tex]
Therefore, the periods of motion for the respective lengths are:
[tex]1.000m: 1.996s[/tex]
[tex]0.750m: 1.732s[/tex]
[tex]0.500m: 1.422s[/tex]
It is important to note that the period of a simple pendulum depends on the length of the string. As the length decreases, the period decreases, indicating faster oscillations. This observation is consistent with the measured results, where the period decreases as the length of the pendulum decreases.
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