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A toy rocket is shot vertically into the air from a launching pad 9 feet above the ground with an initial velocity of feet per second. The height \( h \), in feet, of the rocket above the ground at \( t \) seconds after launch is given by the function:

\[ h(t) = -16t^2 + 32t + 9 \]

How long will it take the rocket to reach its maximum height? What is the maximum height?

Answer :

Final answer:

The rocket will reach its maximum height 1 second after launch. The maximum height of the rocket is 57 feet.

Explanation:

To find the time it takes for the rocket to reach its maximum height, we need to find the vertex of the quadratic function representing the height of the rocket. The vertex of a quadratic function in the form h(t) = at^2 + bt + c is given by t = -b / (2a). In this case, a = -16 and b = 32, so t = -32 / (2*-16) = 1. The rocket will reach its maximum height 1 second after launch.

To find the maximum height, we substitute the time t = 1 into the height function h(t) = -16t^2 + 32t + 9. Therefore, h(1) = -16(1)^2 + 32(1) + 9 = 16 + 32 + 9 = 57 feet. The maximum height of the rocket is 57 feet.

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