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Answer :
The pressure inside the container is 1543.84 atm.
The pressure inside a 39.5 L container holding 100.5 kg of argon gas at 21.0 °C can be calculated using the ideal gas law, PV=nRT.
First, we need to convert the given values to the appropriate units for the ideal gas law.
- Volume (V) = 39.5 L
- Mass (m) = 100.5 kg = 100500 g
- Temperature (T) = 21.0 °C = 294.15 K
Next, we need to find the number of moles (n) of argon gas using the molar mass of argon (39.95 g/mol):
n = m / M = 100500 g / 39.95 g/mol = 2515.64 mol
Now we can plug in the values into the ideal gas law and solve for pressure (P):
PV = nRT
P = (nRT) / V = (2515.64 mol)(0.08206 L·atm/mol·K)(294.15 K) / 39.5 L = 1543.84 atm
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