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Identify the expression equivalent to [tex]\frac{\log _2 128}{\log _2 16}[/tex].

A. [tex]\log _{128} 16[/tex]
B. [tex]\log _4 128[/tex]
C. [tex]\log _2 128[/tex]
D. [tex]\log _{16} 128[/tex]

Answer :

To solve the problem of identifying an equivalent expression to [tex]\(\frac{\log_2 128}{\log_2 16}\)[/tex], we can simplify and evaluate this expression using logarithmic properties. Here's how you can do it:

1. Evaluate the Numerator and Denominator:
- [tex]\(\log_2 128\)[/tex]: Since [tex]\(128 = 2^7\)[/tex], we know that [tex]\(\log_2 128 = 7\)[/tex].
- [tex]\(\log_2 16\)[/tex]: Since [tex]\(16 = 2^4\)[/tex], we know that [tex]\(\log_2 16 = 4\)[/tex].

2. Simplify the Expression:
- Now, replace the logs with their values: [tex]\(\frac{\log_2 128}{\log_2 16} = \frac{7}{4}\)[/tex].

3. Expression in Terms of Another Logarithm:
- By the change of base formula, [tex]\(\frac{\log_2 128}{\log_2 16}\)[/tex] simplifies to [tex]\(\log_{16} 128\)[/tex].

4. Final Answer:
- Therefore, the expression equivalent to [tex]\(\frac{\log_2 128}{\log_2 16}\)[/tex] is [tex]\(\log_{16} 128\)[/tex].

In summary, [tex]\(\log_{16} 128\)[/tex] is the correct answer.

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