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Answer :
To determine which tank is leaking faster, we need to find out the rate at which each tank is losing water. We do this by calculating the leak rate for both Tank A and Tank B in gallons per minute. Here’s a step-by-step solution:
1. Tank A:
- Tank A has leaked [tex]\( \frac{1}{16} \)[/tex] of a gallon in [tex]\( \frac{1}{12} \)[/tex] minute.
- To find the rate of leaking in gallons per minute, divide the volume leaked by the time taken:
[tex]\[
\text{Rate for Tank A} = \frac{\frac{1}{16} \text{ gallon}}{\frac{1}{12} \text{ minute}}
\][/tex]
- To simplify the rate, multiply by the reciprocal of time:
[tex]\[
\text{Rate for Tank A} = \frac{1}{16} \times \frac{12}{1} = 0.75 \text{ gallons per minute}
\][/tex]
2. Tank B:
- Tank B has leaked [tex]\( \frac{3}{80} \)[/tex] of a gallon in [tex]\( \frac{1}{30} \)[/tex] minute.
- To find the rate for Tank B, divide the volume leaked by the time taken:
[tex]\[
\text{Rate for Tank B} = \frac{\frac{3}{80} \text{ gallon}}{\frac{1}{30} \text{ minute}}
\][/tex]
- To simplify the rate, multiply by the reciprocal of time:
[tex]\[
\text{Rate for Tank B} = \frac{3}{80} \times \frac{30}{1} = 1.125 \text{ gallons per minute}
\][/tex]
3. Comparison:
- Now compare the leak rates of both tanks:
- Rate for Tank A is 0.75 gallons per minute.
- Rate for Tank B is 1.125 gallons per minute.
4. Conclusion:
- Since 1.125 gallons per minute (Tank B) is greater than 0.75 gallons per minute (Tank A), Tank B is leaking faster.
Thus, the tank that is leaking faster is Tank B.
1. Tank A:
- Tank A has leaked [tex]\( \frac{1}{16} \)[/tex] of a gallon in [tex]\( \frac{1}{12} \)[/tex] minute.
- To find the rate of leaking in gallons per minute, divide the volume leaked by the time taken:
[tex]\[
\text{Rate for Tank A} = \frac{\frac{1}{16} \text{ gallon}}{\frac{1}{12} \text{ minute}}
\][/tex]
- To simplify the rate, multiply by the reciprocal of time:
[tex]\[
\text{Rate for Tank A} = \frac{1}{16} \times \frac{12}{1} = 0.75 \text{ gallons per minute}
\][/tex]
2. Tank B:
- Tank B has leaked [tex]\( \frac{3}{80} \)[/tex] of a gallon in [tex]\( \frac{1}{30} \)[/tex] minute.
- To find the rate for Tank B, divide the volume leaked by the time taken:
[tex]\[
\text{Rate for Tank B} = \frac{\frac{3}{80} \text{ gallon}}{\frac{1}{30} \text{ minute}}
\][/tex]
- To simplify the rate, multiply by the reciprocal of time:
[tex]\[
\text{Rate for Tank B} = \frac{3}{80} \times \frac{30}{1} = 1.125 \text{ gallons per minute}
\][/tex]
3. Comparison:
- Now compare the leak rates of both tanks:
- Rate for Tank A is 0.75 gallons per minute.
- Rate for Tank B is 1.125 gallons per minute.
4. Conclusion:
- Since 1.125 gallons per minute (Tank B) is greater than 0.75 gallons per minute (Tank A), Tank B is leaking faster.
Thus, the tank that is leaking faster is Tank B.
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