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Answer :
The current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.
When three resistors are connected in series with a six resistor and a 12-volt battery, the total resistance of the series circuit is R = R1 + R2 + R3 + ...
The current flowing through the circuit is the same at every point. So, if we want to know the current flowing through each resistor, we need to use Ohm's law, I = V/R, where V is the voltage of the battery and R is the resistance of each resistor.
I1 = V/R1 = 12/3 = 4 AI2 = V/R2 = 12/6 = 2 AI3 = V/R3 = 12/3 = 4 A. The voltage drop across each resistor can be calculated using Ohm's law, V = IR.
V1 = I1R1 = 4 x 3 = 12 VV2 = I2R2 = 2 x 6 = 12 VV3 = I3R3 = 4 x 3 = 12 V.
Therefore, the current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.
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