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A 270-kg piano is lifted straight up a height of 17.1 m by a motor. The process takes 185 seconds. Assume that the piano is at rest at the start and the end. Assuming the motor is 100% efficient, what is the power required to lift the piano as described?

Answer :

Final answer:

The power required to lift the piano is 24.88 W.

Explanation:

To calculate the power required to lift the piano, we need to calculate the work done and divide it by the time taken. The work done can be calculated as the product of force and distance. In this case, the force is equal to the weight of the piano, which is equal to the mass of the piano multiplied by the acceleration due to gravity. The distance is the height the piano is lifted. So, the work done is given by:

Work = Force * Distance = (270 kg * 9.8 m/s^2) * 17.1 m = 4596.18 J

Now, we can divide the work done by the time taken to find the power:

Power = Work / Time = 4596.18 J / 185 s = 24.88 W

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