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Answer :
Answer : 5.405 moles of [tex]H_2O[/tex] are equivalent to 97.3 grams of [tex]H_2O[/tex]
Solution : Given,
Mass of [tex]H_2O[/tex] = 97.3 g
Molar mass of [tex]H_2O[/tex] = 18 g/mole
Formula used :
[tex]\text{ Number of moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}[/tex]
or,
[tex]\text{ Number of moles of }H_2O=\frac{\text{ Given mass of }H_2O}{\text{ Molar mass of }H_2O}[/tex]
Now put all the given values in this formula, we get the moles of [tex]H_2O[/tex]
[tex]\text{ Number of moles of }H_2O=\frac{97.3g}{18g/mole}=5.405moles[/tex]
Therefore, 5.405 moles of [tex]H_2O[/tex] are equivalent to 97.3 grams of [tex]H_2O[/tex]
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