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What is the surface area of this triangular prism, rounded to the nearest tenth?

A) 18.5 m²
B) 36.9 m²
C) 43.6 m²
D) 87.2 m²

Dimensions:
Length: 5.3 m
Height: 1.26 m
Width: 3.3 m

Answer :

The surface area of this triangular prism is 43.6 square meters.

Given

The measure of the length of the triangular prism is 5.3, height is 1.26, and width is 3.3,

Surface area triangular prism;

The surface area of a triangular prism is the total area covered by its surface in a three-dimensional plane.

The surface area of a triangular prism is given by;

[tex]\rm Surface\ area = bh + (a + b + c)H[/tex]

Where a, b, and c are the sides of triangular bases and H is the height of the prism.

The measured side a is 5.3, b is 3.6, and c is 2.3.

Substitute all the values in the formula;

[tex]\rm Surface\ area = bh + (a + b + c)H\\\\\rm Surface\ area = (5.3)(1.26) + (5.3 + 3.6 + 2.3)(3.3) \\\\Surface \ area =6.6+(11.2) \times (3.3)\\\\Surface \ area =6.6+37\\\\Surface \ area =43.6[/tex]

Hence, the surface area of this triangular prism is 43.6 square meters.

To know more about the surface area of the prism click the link given below.

https://brainly.com/question/1980433

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Rewritten by : Barada

Answer:

The answer is 43.6 m2

Step-by-step explanation:

SA = bh + (s1 + s2 + s3)H

SA = (5.3)(1.26) + (5.3 + 3.6 + 2.3)(3.3) = 43.638