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A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 L to 2.00 L at constant temperature. After the compression, the gas pressure was __________ atm.

Answer :

Answer: 16 atm
Explanation:
P1V1 = P2V2
P2 = P1V1/V2
=4 atm x 8.00 L/2.00L = 16 atm

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Final answer:

Using Boyle's law, you can calculate the final pressure after the compression of the gas sample to be 16.00 atm, assuming that the gas behaves ideally.

Explanation:

This question can be solved using Boyle's law, which states that the pressure and volume of a gas have an inverse relationship when temperature is kept constant. Boyle's law can be expressed as P1V1=P2V2. In this case, the gas initially has a pressure (P1) of 4.00 atm and a volume (V1) of 8.00 l. After compression, the volume (V2) is 2.00 l and we're asked to find the final pressure (P2).

Substituting the values into the formula, we'll have (4.00 atm) x (8.00 l) = P2 x (2.00 l). This finally yields P2 = 16.00 atm.

Note that this approach assumes that the gas behaves ideally. In reality, gases will deviate from ideal behavior (as stated by the ideal gas law), due to the fact that real gases have volume and intermolecular attractions. However, for most purposes and particularly at relatively high temperature and low pressure, the ideal gas approximation is quite accurate.

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