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Answer :
Final answer:
To provide 370 grams of dextrose in a 2-in-1 parenteral nutrition order using D50%, 740 mL of D50% solution is required.
Explanation:
To calculate how many milliliters of D50% (which is a 50% dextrose solution) are needed to provide 370 grams of dextrose, we use the following steps:
Firstly, determine the concentration of dextrose in the D50% solution. Since it's a 50% solution, this means there are 50 grams of dextrose per 100 mL of solution.
Next, calculate the total volume of D50% needed to provide the prescribed amount of dextrose: (370 grams) ÷ (50 grams/100 mL) = 740 mL of D50%
This calculation assumes that the density of the D50% solution is such that 1 mL of solution contains 0.5 grams of dextrose, which is typical for parenteral nutrition preparations.
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